# How do you solve #| 2x + 1 | <| 3x - 2 | #?

##### 1 Answer

#### Answer:

#### Explanation:

First find the zeros of each expression in the modules:

Now we must divide the inequation in three parts:

1) When x>=2/3, both expression are larger than 0, therefore:

is equivalent to:

2)if

3x-2 will be <=0, therefore

3)if

both expressions are negative so we must get the inverse for both ones:

Now the solution is the union of the three solutions: