# How do you solve 2x+1=8?

May 24, 2018

See a solution process below:

#### Explanation:

First, subtract $\textcolor{red}{1}$ from each side of the equation to isolate the $x$ term while keeping the equation balanced:

$2 x + 1 - \textcolor{red}{1} = 8 - \textcolor{red}{1}$

$2 x + 0 = 7$

$2 x = 7$

Now, divide each side of the equation by $\textcolor{red}{2}$ to solve for $x$ while keeping the equation balanced:

$\frac{2 x}{\textcolor{red}{2}} = \frac{7}{\textcolor{red}{2}}$

$\frac{\textcolor{red}{\cancel{\textcolor{b l a c k}{2}}} x}{\cancel{\textcolor{red}{2}}} = \frac{7}{2}$

$x = \frac{7}{2}$

May 24, 2018

$x = \frac{7}{2}$

#### Explanation:

The first step is to get $x$ by itself. You subtract the $1$ from both sides

$2 x + 1 - 1 = 8 - 1$

So now you only have

$2 x = 7$

You divide both sides by $2$ to get $x$ by itself.

$\frac{2 x}{2} = \frac{7}{2}$

$x = 3.5$