Question

How do you solve `2x ^ { 2} + 10x - 168= 0`?

Answer 1

`**x = -12, 7**`

Explanation:

`2x^2+10x-168=0`. Dividing by 2,
`x^2+5x-84=0`

`x^2+12x-7x-84=0`

`x(x+12)-7(x+12)=0`

`(x+12)(x-7)=0`
`x = -12, 7`