# How do you solve 2x ^ { 2} + 10x - 168= 0?

Oct 16, 2017

$\ast x = - 12 , 7 \ast$

#### Explanation:

$2 {x}^{2} + 10 x - 168 = 0$. Dividing by 2,
${x}^{2} + 5 x - 84 = 0$

${x}^{2} + 12 x - 7 x - 84 = 0$

$x \left(x + 12\right) - 7 \left(x + 12\right) = 0$

$\left(x + 12\right) \left(x - 7\right) = 0$
$x = - 12 , 7$