# How do you solve 2x^2 = 16?

Aug 2, 2015

$x = 2 \sqrt{2} , - 2 \sqrt{2}$

#### Explanation:

$2 {x}^{2} = 16$

Divide both sides of the equation by $2$.

${x}^{2} = \frac{16}{2}$ =

${x}^{2} = 8$

Take the square root of both sides.

$x = \pm \sqrt{8}$

$x = \pm \sqrt{2 \times 2 \times 2}$

$x = \pm \sqrt{{2}^{2} \times 2}$

Apply the rule $\sqrt{{a}^{2}} = a$.

$x = \pm 2 \sqrt{2}$

Solve for $x$.

$x = 2 \sqrt{2}$

$x = - 2 \sqrt{2}$