Question

How do you solve `2x^2 + 18x = 20`?

Answer 1

`x=-10`
`x=1`

Explanation:

In order to solve this you must factor it.
1. Subtract the 20 to the left side of the equation.

`2x^2+18x-20=0`

1. Divide all by 2 in order to isolate the x^2

`(cancel(2)(x^2+9x-10))/cancel(2)=0/2`

1. Factor.
   You must find 2 numbers that add to 9 and multiply to -10.

Those two factors would `10` and `-1`.

add them to `x` and set to 0

`(x+10)(x+ -1)=0`

`color(white)(0)x + 10 = 0` `color(white)(0000)`and`color(white)(000)` `x + -1 = 0`

1. Solve.
   `x=-10`
   `x=1`