# How do you solve 2x^2 - 2x = 1?

##### 1 Answer
May 31, 2015

$y = 2 {x}^{2} - 2 x - 1 = 0$

$D = {d}^{2} = {b}^{2} - 4 a c = 4 + 8 = 12 - \to d = 2 \sqrt{3}$

$x = - \frac{b}{2 a} \pm \frac{d}{2 a} = \frac{1}{2} \pm \frac{\sqrt{3}}{2}$