# How do you solve 2x^2 - 32 = 0?

Apr 17, 2016

$x = 4 , - 4$

#### Explanation:

You can factor out a 2 as the GCF.

$2 \left({x}^{2} - 16\right) = 0$

${x}^{2} - 16$ is the difference of perfect squares, which are $\left(x - 4\right) \left(x + 4\right)$

Therefore, you now have $2 \left(x - 4\right) \left(x + 4\right)$.

To solve this quadratic means to find the roots of it (the points where the parabola will cross the x-axis).
$x - 4 = 0$
$x = 4$

and

$x + 4 = 0$
$x = - 4$

Therefore, x = -4, 4