How do you solve #2x^2+3x-17=0# by completing the square?

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Answer 1 · 2016-06-18T15:15:21

#x=(-3+-sqrt145)/4#

step by step

#2x^2+3x-17=0#

#2x^2+3x=17#

#x^2+3/2x=17/2#

#x^2+3/2x+9/16=17/2+9/16#

#(x+3/4)^2=145/16#

#x+3/4=+-sqrt145/4#

#x=(-3+-sqrt145)/4#