# How do you solve 2x^2-3x-2=0 using the quadratic formula?

Apr 10, 2016

2 and $- \frac{1}{2}$

#### Explanation:

Use the improved quadratic formula, also called the quadratic formula in intercept form (Google, Yahoo, Bing Search)
$y = 2 {x}^{2} - 3 x - 2 = 0$
$D = {d}^{2} = {b}^{2} - 4 a c = 9 + 16 = 25$ ---> $d = \pm 5$
There are 2 real roots:
$x = - \frac{b}{2 a} \pm \frac{d}{2 a} = \frac{3}{4} \pm \frac{5}{4}$
$x 1 = \frac{8}{4} = 2$
$x 2 = - \frac{2}{4} = - \frac{1}{2}$