# How do you solve #2x^2-4x+8=0 # by completing the square?

##### 1 Answer

Jun 5, 2016

no real solution

#### Explanation:

First, let's divide all terms by 2

Let's add and subtract 1:

so that the initial three terms represent the square of

that's equivalent to:

but this equation has no real solution, because a square is not negative