# How do you solve 2x^2+5x+2=0?

Jul 12, 2015

color(blue)(x=-1/2,x=-2

#### Explanation:

$2 {x}^{2} + 5 x + 2$

Here, we can first factorise the expression and then find the solutions.

Factorising by splitting middle term

$2 {x}^{2} + \textcolor{g r e e n}{5 x} + 2 = 0$

$2 {x}^{2} + \textcolor{g r e e n}{4 x + x} + 2 = 0$

$2 x \left(x + 2\right) + 1 \left(x + 2\right) = 0$

$\left(2 x + 1\right) \left(x + 2\right) = 0$
Now, we equate the factors with zero to find the solutions.

2x+1=0, color(blue)(x=-1/2
x+2=0 , color(blue)(x=-2