# How do you solve 2x^2= 5x-9 using the quadratic formula?

$2 {x}^{2} - 5 x + 9 = 0$
$a = 2 , b = - 5 , c = 9 , x = \frac{5 \pm \sqrt{25 - 4 \cdot 2 \cdot 9}}{4}$
$x = \frac{5 \pm \sqrt{- 47}}{4} = n o s o l u t i o n$