# How do you solve 2x^2-67=0?

$x = \pm \sqrt{\frac{67}{2}}$
$2 {x}^{2} - 67 = 0$
$2 {x}^{2} = 67$
${x}^{2} = \frac{67}{2}$
$x = \pm \sqrt{\frac{67}{2}}$