How do you solve #-2x^2-7x=-1.5# using the quadratic formula?

1 Answer
Aug 25, 2017

Answer:

#x~~ -3.7,x~~ 0.2#

Explanation:

#"rearrange and equate to zero"#

#rArr-2x^2-7x+1.5=0#

#"with "a=-2,b=-7,c=1.5#

#"solving using the "color(blue)"quadratic formula"#

#"for the quadratic "ax^2+bx+c=0#

#•color(white)(x)x=(-b+-sqrt(b^2-4ac))/(2a)#

#rArrx=(7+-sqrt(49+12))/(-4)#

#rArrx=(7+sqrt61)/(-4)" or "x=(7-sqrt61)/(-4)#

#rArrx~~ -3.7" to 1 dec. place or "x~~ 0.2" to 1 dec. place"#