# How do you solve 2x^2 - 8x = 22 by completing the square?

$x = 5.87 \left(2 \mathrm{dp}\right) \mathmr{and} x = - 1.87 \left(2 \mathrm{dp}\right)$
$2 \left({x}^{2} - 4 x + 4\right) = 22 + 8 \mathmr{and} 2 {\left(x - 2\right)}^{2} = 30 \mathmr{and} {\left(x - 2\right)}^{2} = 15 \mathmr{and} x - 2 = \pm \sqrt{15} \mathmr{and} x = 2 + \sqrt{15} = 5.87 \left(2 \mathrm{dp}\right) \mathmr{and} x = 2 - \sqrt{15} = - 1.87 \left(2 \mathrm{dp}\right)$[Ans]