How do you solve #2x^2 + 8x - 3 = 0# using the quadratic formula?

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Answer 1 · 2016-08-06T07:53:40

#x=2-sqrt22/2# or #x=2+sqrt22/2#

Quadratic formula gives the solution of quadratic equation #ax^2+bx+c=0# as #x=(-b+-sqrt(b^2-4ac))/(2a)#.

Hence solution of #2x^2+8x-3=0# using the formula is given by

#x=(-8+-sqrt(8^2-4xx2xx(-3)))/(2xx2)# or

#x=(-8+-sqrt(64+24))/4# or

#x=(-8+-sqrt88)/4# or

#x=-2+-sqrt(4xx22)/4=2+-2/4sqrt22# or

#x=2+-sqrt22/2# i.e.

#x=2-sqrt22/2# or #x=2+sqrt22/2#