Question

How do you solve `2x^2 - 9x + 7 = 0`?

Answer 1

This equation has solutions `x=7/2` and `x=1`

Explanation:

Notice that `9 = 2+7`.

So we find:

`0 = 2x^2-9x+7`

`= 2x^2-2x-7x+7`

`= 2x(x-1)-7(x-1)`

`= (2x-7)(x-1)`

Hence zeros: `x=7/2` and `x=1`