How do you solve 2x^2 - 9x + 7 = 0?

Aug 6, 2016

This equation has solutions $x = \frac{7}{2}$ and $x = 1$

Explanation:

Notice that $9 = 2 + 7$.

So we find:

$0 = 2 {x}^{2} - 9 x + 7$

$= 2 {x}^{2} - 2 x - 7 x + 7$

$= 2 x \left(x - 1\right) - 7 \left(x - 1\right)$

$= \left(2 x - 7\right) \left(x - 1\right)$

Hence zeros: $x = \frac{7}{2}$ and $x = 1$