How do you solve 2x^2-x= -52x2x=5 using the quadratic formula?

1 Answer
Aug 12, 2015

The solutions are:
color(blue)(x= (1+sqrt(-39))/4, x=(1-sqrt(-39))/4x=1+394,x=1394

Explanation:

2x^2 - x+5=02x2x+5=0

The equation is of the form color(blue)(ax^2+bx+c=0ax2+bx+c=0 where:
a=2, b=-1, c=5a=2,b=1,c=5

The Discriminant is given by:
Delta=b^2-4*a*c

= (-1)^2-(4*2*5)

= 1-40=-39

The solutions are found using the formula
x=(-b+-sqrtDelta)/(2*a)

x = (-(-1)+-sqrt(-39))/(2*2) = (1+-sqrt(-39))/4

The solutions are:
color(blue)(x= (1+sqrt(-39))/4, x=(1-sqrt(-39))/4