How do you solve #2x^2-x-6=0#?

1 Answer
Jul 3, 2016

Answer:

#x = 2 or -3/2#

Explanation:

This is a quadratic so we expect to obtain two roots. Can recognise that we are able to factorise this to:

#(2x + 3)(x - 2) = 0#

For the left hand side of the equation to equal zero, one of the brackets must evaluate to zero.

The first bracket:

#(2x+3) = 0 implies x = -3/2#

The second:

#(x-2) = 0 implies x = 2#