How do you solve #2x^2-x-6=0#?

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Answer 1 · 2016-07-03T09:50:19

#x = 2 or -3/2#

This is a quadratic so we expect to obtain two roots. Can recognise that we are able to factorise this to:

#(2x + 3)(x - 2) = 0#

For the left hand side of the equation to equal zero, one of the brackets must evaluate to zero.

The first bracket:

#(2x+3) = 0 implies x = -3/2#

The second:

#(x-2) = 0 implies x = 2#