# How do you solve [(2x, 3, 3z)]=[(5,3y,9)]?

Dec 17, 2016

$x = \frac{5}{2} , y = 1 , z = 3$

#### Explanation:

Set each "element" of the first matrix equal to the corresponding element of the second matrix.

$\left[\textcolor{b l u e}{2 x} \textcolor{w h i t e}{a a} \textcolor{red}{3} \textcolor{w h i t e}{a a} \textcolor{g r e e n}{3 z}\right] = \left[\textcolor{b l u e}{5} \textcolor{w h i t e}{a a} \textcolor{red}{3 y} \textcolor{w h i t e}{a a} \textcolor{g r e e n}{9}\right]$

$\textcolor{b l u e}{2 x} = \textcolor{b l u e}{5} \implies \textcolor{b l u e}{x} = \frac{5}{2}$

$\textcolor{red}{3} = \textcolor{red}{3 y} \implies \textcolor{red}{y} = 1$

$\textcolor{g r e e n}{3 z} = \textcolor{g r e e n}{9} \implies \textcolor{g r e e n}{z} = 3$