How do you solve #-2x - 4y + 2z = -8#, #-x - 5y +12z = 5#, #3x + 5y - z = 10#?
From the given equations
We eliminate the variable x first
multiply the terms of the second equation by 2 then subtract it from the first equation
multiply the original second equation by 3 then add to the third equation
Multiply this fifth equation by 3 then add to the fourth equation
the result is
Using the reduced fifth equation
Using the original second equation
the solution is
God bless...I hope the explanation is useful..