How do you solve #2x - 7= 41#?

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Answer 1 · 2017-07-22T17:40:35

See a solution process below:

Step 1) Add #color(red)(7)# to each side of the equation to islate the #x# term while keeping the equation balanced:

#2x - 7 + color(red)(7) = 41 + color(red)(7)#

#2x - 0 = 48#

#2x = 48#

Step 2) Divide each side of the equation by #color(red)(2)# to solve for #x# while keeping the equation balanced:

#(2x)/color(red)(2) = 48/color(red)(2)#

#(color(red)(cancel(color(black)(2)))x)/cancel(color(red)(2)) = 24#

#x = 24#