# How do you solve 2x + 7 \leq 19?

Oct 8, 2017

$x \le 6$

#### Explanation:

First, minus the 7 from both sides of the equation and get this:
$2 x \le 12$

Then divide both sides by 2 to get x on itself and get the answer:
$x \le 6$

Oct 8, 2017

$x \le 6$

#### Explanation:

2x+7≤19
Subtract 7 from both sides.

2x+7-7≤19-7

$2 x \le 12$

$\frac{2 x}{2 x} \le \frac{12}{2 x}$

$x \le 6$

Oct 8, 2017

$x \le q 6$

#### Explanation:

To start, pretend the$\le q$symbol is really and$=$symbol, and then solve it like a normal algebra equation:

Start with $2 x + 7 \le q 19$.

Replace$\le q$with$=$:

$2 x + 7 = 19$

Subtract 7 from both sides to isolate $x$:

$2 x = 12$

Divide both sides by $2$ to get $x$ to be just $x$, with no coefficients or other terms:

$x = 6$

Replace$=$with$\le q$:

$x \le q 6$

(If you had multiplied or divided by a negative number, you would have had to flip the inequality sign to$\ge q$. But you didn't have to, so you're good.)