How do you solve #-2x + 8\leq 24#?

1 Answer
Jun 21, 2018

Answer:

#x >= -8#

Explanation:

#-2x + 8 <= 24#

Subtract #color(blue)8# from both sides:
#-2x + 8 quadcolor(blue)(-quad8) <= 24 quadcolor(blue)(-quad8)#

#-2x <= 16#

Now we have to divide both sides by #-2#. However, in inequalities, when you multiply or divide both sides by a negative number, you have to switch the inequality sign. So the #<=# becomes #>=#:
#(-2x)/color(blue)(-2) color(blue)(>=) 16/color(blue)(-2)#

Therefore,
#x >= -8#

Hope this helps!