How do you solve #2x – 8y = 8# and #-x + 4y = 4 #?
You need to manipulate the equations just a bit
The equations given:
may be put in a more convenient form. For example, if we divide the whole first equation by 2, the solutions don't change:
so now we can add the two equations and eliminate
which is false. The answer is then that the system given has no solutions.