Question

How do you solve `2y = 3y^2`?

Answer 1

`y=0, 3/2`

Explanation:

Divide both sides by `y:`

`(2cancely)/cancely=(3y^((cancel2)1))/cancely`

`3y=2`

`y=2/3` will be one solution.

`y=0` is also a solution. Since both sides originally include an instance of `y, y=0` results in `0=0,`a valid solution.