How do you solve 2y = 3y^2?

Apr 1, 2018

$y = 0 , \frac{3}{2}$

Explanation:

Divide both sides by $y :$

$\frac{2 \cancel{y}}{\cancel{y}} = \frac{3 {y}^{\left(\cancel{2}\right) 1}}{\cancel{y}}$

$3 y = 2$

$y = \frac{2}{3}$ will be one solution.

$y = 0$ is also a solution. Since both sides originally include an instance of $y , y = 0$ results in $0 = 0 ,$a valid solution.