How do you solve #3^(1-2x)=243#? Precalculus Properties of Logarithmic Functions Natural Logs 1 Answer Narad T. Nov 27, 2016 The answer is #x=-2# Explanation: Note that #243=3*3*3*3*3=3^5# Our equation is #3^(1-2x)=243# #3/3^(2x)=3^5# #3^(2x)=3/3^5=3^(-4)# So, #2x=-4# #x=-2# Answer link Related questions What is the natural log of e? What is the natural log of 2? How do I do natural logs on a TI-83? How do I find the natural log of a fraction? What is the natural log of 1? What is the natural log of infinity? Can I find the natural log of a negative number? How do I find a natural log without a calculator? How do I find the natural log of a given number by using a calculator? How do I do natural logs on a TI-84? See all questions in Natural Logs Impact of this question 5592 views around the world You can reuse this answer Creative Commons License