How do you solve #-3 (1- 6k) = 6k + 21#?

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Answer 1 · 2015-11-20T03:37:00

#color(blue)(k=2#

#−3(1−6k)=6k+21#

#−3*1 + (-3) * (−6k)=6k+21#

#−3 + 18k=6k+21#

#18k - 6k = 21+3#

#12k = 24#

#k=24/12#

#color(blue)(k=2#