How do you solve #3+2/3x=5/6x-7/8#?

1 Answer
Sep 14, 2016

#x=93/4#

Explanation:

#color(blue)("Method: ")#

Make them all have a common denominator.

Then just equate the numerators to each other.

Isolate #x #

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("Determining the value of "x)#

I choose 24 as the common denominator

#color(white)(.)color(brown)( (3color(blue)(xx1))color(white)(...)+x(2/3color(blue)(xx1))color(white)(.)=x(5/6color(blue)(xx1))color(white)(.)-(7/8color(blue)(xx1)))#

#color(brown)( (3color(blue)(xx24/24))+x(2/3color(blue)(xx8/8))=x(5/6color(blue)(xx4/4))-(7/8color(blue)(xx3/3)))#

#" "72/24" "+" "16/24 x" "=" "20/24x" "-" "21/24#

Multiplying both sides by 24 removing the denominator.

#=>72+16x=20x-21 #

Subtract #16x# from both sides

#=>72=4x-21#

Add 21 to both sides

#=>93=4x#

Divide both sides by 4

#93/4=x#

Write as: #x=93/4#