How do you solve #|3/2(x-2)|+3=2#?

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Answer 1 · 2016-09-10T13:41:04

#x = 1 1/3 =4/3#
OR
# x = 2 2/3 = 8/3#

Recall: #abs(a+b) = +-c#

#abs(3/2(x-2)) = -1#

#3/2(x-2) = +-(-1)#

Either

#3/2(x-2) = +(-1) = -1#

#x-2 = -2/3#

#x = 2-2/3#

#x = 1 1/3 =4/3#

OR

#3/2(x-2) = -(-1) = 1#

#x-2 = 2/3#

#x = 2+2/3#

#x = 2 2/3 = 8/3#