Question

How do you solve `3- 2( x + 6) = - 1( x - 1) + 7`?

Answer 1

`x=-17`

Explanation:

`"distribute parenthesis on both sides of the equation"`

`3-2x-12=-x+1+7larrcolor(blue)"collect like terms"`

`rArr-2x-9=-x+8`

`"add 2x to both sides"`

`cancel(-2x)cancel(+2x)-9=2x-x+8`

`rArr-9=x+8`

`"subtract 8 from both sides"`

`-9-8=xcancel(+8)cancel(-8)`

`rArr-17=xrArrx=-17`

`color(blue)"As a check"`

Substitute this value into the equation and if both sides are equal then it is the solution.

`"left "=3-(2xx-11)=3-(-22)=3+22=25`

`"right "=(-1xx-18)+7=18+7=25`

`rArrx=-17" is the solution"`

Answer 2

`x=-17`

Explanation:

`3-2(x+6)=-1(x-1)+7`

`3-2x-12=-x+1+7`

`-2x-9=-x+8`

`-9=x+8`

`x=-9-8`

`x=-17`