How do you solve #3( 2t + 6) = 0#?

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Answer 1 · 2016-09-22T23:20:59

#x = -3#

To solve:

#3(2x+6) = 0#

Note that the product of #3# and #(2x+6)# can only be #0# if at least one of them is #0#. Now #3 != 0#, so we must have:

#2x+6 = 0#

Subtract #6# from both sides to get:

#2x = -6#

Divide both sides by #2# to find:

#x = -3#