How do you solve #-3( 2x - 3) = 20- 4x#?

1 Answer
Jim G.
Sep 11, 2016

#x=-11/2#

Explanation:

The first step is to distribute the bracket on the left side of the equation.

#rArr-6x+9=20-4x#

We now want the terms in x on the left and numeric values on the right.

add 4x to both sides of the equation.

#-6x+4x+9=20cancel(-4x)cancel(+4x)#

#rArr-2x+9=20#

To isolate - 2x on left, subtract 9 from both sides.

#-2xcancel(+9)cancel(-9)=20-9#

#rArr-2x=11#

now divide both sides by - 2 to solve for x.

#(cancel(-2) x)/cancel(-2)=11/(-2)#

#rArrx=-11/2" is the solution"#

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