# How do you solve 3( 2x + 3x + 2) = - 4x + 124?

May 28, 2018

$x = \frac{118}{19}$

#### Explanation:

First, expand by multiplying $3$ by every term in the brackets. Then group together the terms with $x$ in them and group the terms without $x$s in them together.

Finally, divide the number in front of the $x$ by the number on the other side to solve for $x$.

$3 \left(2 x + 3 x + 2\right) = - 4 x + 124$

$3 \cdot 2 x + 3 \cdot 3 x + 3 \cdot 2 = - 4 x + 124$

$6 x + 9 x + 6 = - 4 x + 124$

$15 x + 6 = - 4 x + 124$

$15 x + 4 x = 124 - 6$

$19 x = 118$

$x = \frac{118}{19} = 6.21$