How do you solve #-3( 2x + 5) \geq 3x + 3#?

1 Answer
Mar 26, 2018

Answer:

#x <=-2#

Explanation:

Start out by using the distributive property and multiply #-3# by the numbers in the parentheses.

#-3(2x + 5) >= 3x + 3#

#-6x - 15 >= 3x + 3#

Now finish simplifying:

#-6x - 15 >= 3x + 3#

#-9x - 15 >= 3#

#-9x >= 18#

#-x >= 2#

We want #x# to be positive, not negative, so we will multiply both sides by #-1#. But, there's a catch! We need to switch the greater than sign (#>#) to a lesser than sign (#<#) because we did this.

#-x(-1)color(red)>= 2(-1)#

#x color(red)<=-2#

This means that x is less than or equal to -2.