How do you solve #3- 2x = 8+ 2x#?

1 Answer
Jun 5, 2018

#x = -5/4# or about #-1.25#

Explanation:

#3-2x = 8 + 2x#

To solve for the variable #x#, we have to make it by itself. First, subtract #color(blue)(2x)# from both sides of the equation:
#3-2x quadcolor(blue)(-quad2x) = 8 + 2x quadcolor(blue)(-quad2x)#

#3 - 4x = 8#

Now subtract #color(blue)3# from both sides:
#3 - 4x quadcolor(blue)(-quad3) = 8 quadcolor(blue)(-quad3)#

#-4x = 5#

Divide both sides by #color(blue)(-4x)#:
#(-4x)/color(blue)(-4) = 5/color(blue)(-4)#

#x = -5/4# or about #-1.25#

Hope this helps!