How do you solve #3^(2x)=80#?
1 Answer
Feb 15, 2018
Explanation:
#"note that "3^(2x)=(3^2)^x=9^x#
#rArr9^x=80#
#[logx^nhArrnlogx]#
#"take the ln (natural log) of both sides"#
#ln9^x=ln80#
#rArrxln9=ln80#
#rArrx=ln80/ln9~~1.994" to 3 dec. places"#
