# How do you solve 3-2y=2(3y-2)-5y?

Jul 27, 2018

$y = \frac{3}{2}$ or $1.5$

#### Explanation:

$3 - 2 y = 2 \left(3 y - 2\right) - 5 y$

Simplify the right side using the distributive property:
$3 - 2 y = 6 y - 4 - 5$

Simplify the right side:
$3 - 2 y = 6 y - 9$

Subtract $\textcolor{b l u e}{6 y}$ from both sides:
$3 - 2 y \quad \textcolor{b l u e}{- \quad 6 y} = 6 y - 9 \quad \textcolor{b l u e}{- \quad 6 y}$

$3 - 8 y = - 9$

Subtract $\textcolor{b l u e}{3}$ from both sides:
$3 - 8 y \quad \textcolor{b l u e}{- \quad 3} = - 9 \quad \textcolor{b l u e}{- \quad 3}$

$- 8 y = - 12$

Divide both sides by $\textcolor{b l u e}{- 8}$:
$\frac{- 8 y}{\textcolor{b l u e}{- 8}} = \frac{- 12}{\textcolor{b l u e}{- 8}}$

$y = \frac{12}{8}$

$y = \frac{3}{2}$ or $1.5$

Hope this helps!