# How do you solve 3/4q-7=8?

##### 1 Answer
Jan 16, 2017

See entire solution process below:

#### Explanation:

First, add $\textcolor{red}{7}$ to each side of the equation to isolate the $q$ term and keep the equation balanced:

$\frac{3}{4} q - 7 + \textcolor{red}{7} = 8 + \textcolor{red}{7}$

$\frac{3}{4} q - 0 = 15$

$\frac{3}{4} q = 15$

Next, multiply each side of the equation by $\frac{\textcolor{red}{4}}{\textcolor{b l u e}{3}}$ to solve for $q$ while keeping the equation balanced:

$\frac{\textcolor{red}{4}}{\textcolor{b l u e}{3}} \times \frac{3}{4} q = \frac{\textcolor{red}{4}}{\textcolor{b l u e}{3}} \times 15$

$\frac{\cancel{\textcolor{red}{4}}}{\cancel{\textcolor{b l u e}{3}}} \times \frac{\textcolor{b l u e}{\cancel{\textcolor{b l a c k}{3}}}}{\textcolor{red}{\cancel{\textcolor{b l a c k}{4}}}} q = \frac{\textcolor{red}{4}}{\textcolor{b l u e}{3}} \times \left(3 \times 5\right)$

$q = \frac{\textcolor{red}{4}}{\cancel{\textcolor{b l u e}{3}}} \times \left(\textcolor{b l u e}{\cancel{\textcolor{b l a c k}{3}}} \times 5\right)$

$q = 4 \times 5$

$q = 20$