# How do you solve 3(4x-2)=-2(-6x+3)?

Dec 15, 2016

$x$ = any value

#### Explanation:

multiply out brackets:

$3 \left(4 x - 2\right) = 12 x - 6$

$12 x - 6 = - 2 \left(- 6 x + 3\right)$

$- 2 \left(- 6 x + 3\right) = 12 x - 6$

$12 x - 6 = 12 x - 6$

Since both equations are the same, $x$ could have any value and still satisfy this system of equations.