# How do you solve 3-5y=0?

Nov 28, 2016

$y = \frac{3}{5}$

#### Explanation:

Leave the 3 where it is and add 5y to both sides of the equation.

$3 \cancel{- 5 y} \cancel{+ 5 y} = 0 + 5 y$

$\Rightarrow 3 = 5 y$

To solve for y, divide both sides by 5

$\frac{3}{5} = \frac{\cancel{5} y}{\cancel{5}}$

$\Rightarrow y = \frac{3}{5} \text{ is the solution}$

Nov 28, 2016

Add terms to both side and/or multiply both sides by the appropriate factor, until you have an expression of $y$

#### Explanation:

Start from:

$3 - 5 y = 0$

Add $- 3$ to both sides of the equation:

$3 - 5 y - 3 = - 3$

On the left side $3 - 3 = 0$ so you can simplify these two terms and get:

$- 5 y = - 3$

Now multiply both sides by $- \frac{1}{5}$:

$- 5 \left(- \frac{1}{5}\right) y = - 3 \left(- \frac{1}{5}\right)$

or $y = \frac{3}{5}$