How do you solve #3- 6b \leq - 51#?

1 Answer
Dec 13, 2017

See a solution process below:

Explanation:

First, subtract #color(red)(3)# from each side of the inequality to isolate the #b# term while keeping the inequality balanced:

#-color(red)(3) + 3 - 6b <= -color(red)(3) - 51#

#0 - 6b <= -54#

#-6b <= -54#

Next, divide both sides of the inequality by #color(blue)(-6)# to solve for #b# while keeping the inequality balanced. However, because we are multiplying or dividing an inequality by a negative number we must reverse the inequality operator:

#(-6b)/color(blue)(-6) color(red)(>=) (-54)/color(blue)(-6)#

#(color(blue)(cancel(color(black)(-6)))b)/cancel(color(blue)(-6)) color(red)(>=) 9#

#b >= 9#