How do you solve #3,888= 48( p + 15)#?

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Answer 1 · 2016-12-23T19:51:20

#p = 66#

First, expand the term in parenthesis by multiplying each term by #color(red)(48)#:

#3888 = (color(red)(48) * p) + (color(red)(48) * 15)#

#3888 = 48p + 720#

Now we can isolate the #p# term while keeping the equation balanced:

#3888 - color(red)(720) = 48p + 720 - color(red)(720)#

#3168 = 48p + 0#

#3168 = 48p#

Now we can solve for #p# while keeping the equation balanced:

#3168/color(red)(48) = (48p)/color(red)(48)#

#66 = (color(red)(cancel(color(black)(48)))p)/color(red)(cancel(48))#

#66 = p#

or

#p = 66#