# How do you solve 3-abs(8x-6)=3?

$x = \frac{3}{4}$
$| 8 x - 6 | = 3 - 3 = 0$
but the only number with absolute value $0$ is $0$, so we can drop the absolute value and get $8 x - 6 = 0$, hence $x = \frac{3}{4}$