How do you solve #-3( c + 4) = - 9#?

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Answer 1 · 2018-01-18T06:14:59

#c=-1#

#-3(c+4)=-9#

Start by using the distributive property

#(-3)(c)+(-3)(4)=-9#

#-3c - 12 = -9#

Then #12# to both sides

#-3c - 12 + 12 = -9 + 12#

#3c = 3#

Finally, divide both sides by #-3#

#(cancel(-3)c)/cancel(-3) = 3/-3#

#c=-1#