# How do you solve 3 cot 2x - sqrt 3 = 0?

Jul 24, 2016

$\frac{\pi}{6} + \frac{k \pi}{2}$

#### Explanation:

$3 \cot 2 x - \sqrt{3} = 0$
$\cot 2 x = \frac{\sqrt{3}}{3}$
Trig table --> $\cot \left(\frac{\pi}{3}\right) = \frac{\sqrt{3}}{3}$, then
$2 x = \frac{\pi}{3} + k \pi$
$x = \frac{\pi}{6}$ + (kpi)/2
General answer: $x = \frac{\pi}{6} + \frac{k \pi}{2}$