How do you solve $- 3 (r + 6) = 27$ $-3 (r +6)=27$ ?

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Answer 1 · 2018-05-08T00:41:10

$r = - 15$ $r=-15$

$- 3 (r + 6) = 27$ $-3 (r+6)=27$

We wanna start by using the distributive property

$(- 3) (r) + (- 3) (6) = 27$ $(-3)(r) + (-3)(6) = 27$

#-3r -18 = 27

Add $18$ $18$ on both sides

#-3r - 18 + 18 = 27 + 18

-3r = 45

Divide both sides by $- 3$ $-3$

$(cancel(-3)r)/cancel(-3) = 45/(-3)$

$r=-15$

How do you solve -3 (r +6)=27−3(r+6)=27-3 (r +6)=27?