How do you solve #-3 (r +6)=27#?

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Answer 1 · 2018-05-08T00:41:10

#r=-15#

#-3 (r+6)=27#

We wanna start by using the distributive property

#(-3)(r) + (-3)(6) = 27#

#-3r -18 = 27

Add #18# on both sides

#-3r - 18 + 18 = 27 + 18

-3r = 45

Divide both sides by #-3#

#(cancel(-3)r)/cancel(-3) = 45/(-3)#

#r=-15#