# How do you solve 3 sqrt( 3x-1) =2 ?

Mar 15, 2018

$x = \frac{13}{27}$

#### Explanation:

$3 \sqrt{3 x - 1} = 2$

$\sqrt{3 x - 1} = \frac{2}{3}$

$3 x - 1 = {\left(\frac{2}{3}\right)}^{2}$

$3 x - 1 = \frac{4}{9}$

$3 x = \frac{4}{9} + \frac{9}{9} = \frac{13}{9}$

$x = \frac{13}{27}$

Aug 10, 2018

$x = \frac{13}{27}$

#### Explanation:

To isolate the radical, we can divide both sides by $3$ to get

$\sqrt{3 x - 1} = \frac{2}{3}$

To get rid of the radical, we can square both sides to get

$3 x - 1 = \frac{4}{9}$

Next, let's add $1$ or $\frac{9}{9}$ to both sides to get

$3 x = \frac{13}{9}$

Next, we can multiply both sides by $\frac{1}{3}$ to get

$x = \frac{13}{27}$

Hope this helps!