How do you solve #3 sqrt( 3x-1) =2 #?

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Answer 1 · 2018-03-15T14:42:39

#x= 13/27#

#3sqrt(3x-1)=2#

#sqrt(3x-1)=2/3#

#3x-1=(2/3)^2#

#3x-1=4/9#

#3x=4/9+9/9= 13/9#

#x= 13/27#

Answer 2 · 2018-08-10T03:06:02

#x=13/27#

To isolate the radical, we can divide both sides by #3# to get

#sqrt(3x-1)=2/3#

To get rid of the radical, we can square both sides to get

#3x-1=4/9#

Next, let's add #1# or #9/9# to both sides to get

#3x=13/9#

Next, we can multiply both sides by #1/3# to get

#x=13/27#

Hope this helps!