Question

How do you solve `3(x+1)^2=24`?

Answer 1

`x=-1+-2sqrt2`

Explanation:

`3(x+1)^2=24`
`(x+1)^2=8` `->` divide both sides by `3`
`x+1=sqrt8` `->` take the square root of both sides
`x+1=+-2sqrt2` `->` simplify the left side
`x=-1+-2sqrt2` `->` subtract `1` from both sides

`x=-1+-2sqrt2`