How do you solve #3(x - 1)^2= 27#?

2 Answers
Jun 21, 2018

Answer:

#x = 10#

Explanation:

#3(x-1)^2 = 27#

First, divide both sides by #color(blue)3#:
#(3(x-1)^2)/color(blue)3 = 27/color(blue)3#

#(x-1)^2 = 9#

Now square root both sides:
#sqrt((x-1)^2) = sqrt9#

#x - 1 = \pm3#

Finally, add #color(blue)1# to both sides:
#x - 1 quadcolor(blue)(+quad1) = \pm3 quadcolor(blue)(+quad1)#

Therefore,
#x = 4 or -2#

Hope this helps!

Jun 21, 2018

Answer:

#x=-2" or "x=4#

Explanation:

#"divide both sides by 3"#

#cancel(3)/cancel(3)(x-1)^2=9#

#(x-1)^2=9#

#color(blue)"take the square root of both sides"#

#sqrt((x-1)^2)=+-sqrt9larrcolor(blue)"note plus or minus"#

#x-1=+-3#

#"add 1 to both sides"#

#x=1+-3#

#x=1-3=-2" or "x=1+3=4#